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7(x-4)^2-2x(4x+5)=-29-(x+3)(x-3)
We move all terms to the left:
7(x-4)^2-2x(4x+5)-(-29-(x+3)(x-3))=0
We use the square of the difference formula
x^2+7(x-4)^2-2x(4x+5)+9=0
We multiply parentheses
x^2-8x^2+7(x-4)^2-10x+9=0
We add all the numbers together, and all the variables
-7x^2-10x+7(x-4)^2+9=0
We move all terms containing x to the left, all other terms to the right
-7x^2-10x+7(x-4)^2=-9
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